Question

Wilkinson's catalyst react with $H_2$ to form an octahedral complex in which $Rh(Z=45)$ has the following electronic configuration in the ligand field $T_{2g}^{2,2,2},e_9^{10,10}$. Then which of the following is correct about this new complex.

• A. It is paramagnetic
• B. Its IUPAC name is chlorodihydriodons (triphenylphosphine rhodium $III$)
• C. Hybridisation of Rh$\left(I\right)$ is $d^{2}s{p}^3$
• D. $Noneofthese$

Answer 1

The correct option is A It is paramagnetic

If we see the configuration of produced complex, there is no unpaired electron , hence it would not be paramagnetic in nature. But yes its IUPAC name is chlorodihydriodotris ( triphenylphosphine ) rhodium (III), shown below:-

Option B is correct answer