Question

Willy is 28 years old, but she has celebrated her birthday seven times till now. Considering she celebrates her birthday every time the date came up, on which day was she born?

• A. October 6
• B. December 10
• C. January 28
• D. February 29

Answer 1

The correct option is D February 29

A leap year occurs only once in four years, and the leap day in a leap year is February 29.

So, if Willy was born on February 29, she gets to celebrate her birthday only once in every four years.

$28÷4=7$

Hence, if Willy was born on February 29, she has celebrated her birthday only seven times in 28 years.