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Question

With Baeyer's reagent ethene forms:

A
Ethane-1,2-diol
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B
Oxalic acid
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C
Formic acid
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D
None of the above
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Solution

The correct option is A Ethane-1,2-diol
Baeyer’s reagent: cold & dil. KMnO4
Reaction of Baeyer's reagent with alkene:
CH2=CH2+H2O+[O]Baeyer's reagent−−−−−−−−−OHCH2CH2OH

Oxidation with alkaline KMnO4 give syn-addition product


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