With excess of $C l_{2}$ ammonia forms:

N H_{4} C l

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N_{2}

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N C l_{3}

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N H_{3} N C l_{3}

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Solution

The correct option is C $N C l_{3}$
When excess of $C l_{2}$ reacts with $N H_{3}$ , to give $H C l$ and $N C l_{3}$ gas.
$3 C l_{2} + N H_{3} \to N C l_{3} + 3 H C l$
$N C l_{3}$ is a powerful explosive which is major product of the reaction.

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