With increase of pressure while keeping volume and temperature constant, the mean free path

Decreases

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Increases

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Does not change

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Becomes zero

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Solution

The correct option is A Decreases
For a given volume and temperature, density increases on increasing the pressure.
density, d = $\frac{P M}{R T}$
Thus molecules get closer and hence mean free path decreases.
Detail discussion:
Mean free path is,
l = $\frac{k_{B} T}{\sqrt{2} π d^{2} p}$ where d is diameter of the molecule and $k_{B}$ is Boltzmann constant
From PV = nRT, $\frac{T}{P} = \frac{n R}{V}$
One does not need to remember this formula. This has been shown just to increase the understanding.

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