With respect to air critical angle in a medium for light of red colour [λ1]isθ. Other facts remaining same,critical angle for light of yellow colour [λ2] will be
A
θ
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B
Morethanθ
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C
lessthanθ
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D
θλ1λ2
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Solution
The correct option is Alessthanθ Critical angle =sin−1(1μ) ∴θ=sin−1(1μλ1)andθ′=sin−1(1μλ2) Since μλ2>μλ1, hence θ′<θ