With what minimum acceleration can a fireman slide down a rope whose breaking strength is two third of his weight ?
A
g/2
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B
2g/3
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C
g/3
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D
3g/4
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Solution
The correct option is Cg/3 Heregiven,thefiremanpullstheropeindownwarddirectionbyforce.so,theupwardforce(T)onthefireman−sincethefiremanisacceleratingdownward,so,mg−T=ma⇒mg−23mg=ma∴a=g/3so,thecorrectisC.