With what speed in mileshr must an object be thrown vertically upwards to reach a height of 91.5 m? (Take a=9.8m/s2)
94.3
On reaching maximum height, final velocity = 0
Using third equation of motion, v2=u2+2as
02=u2−2×9.8×91.5
u=42.3ms
Hence, u = 42.3 × 2.23 miles/hr = 94.3 miles/hr.