With what speed in miles/hr must an object be thrown vertically upwards to reach a height of 91.5m.

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Solution

apply equation of motion
v2-u2=2as
v =0
a = -10
-u2 = -21091.5
u = 42.778m/s
u= 95.40 mi/hr

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Similar questions

With what speed in $\frac{m i l e s}{h r}$ must an object be thrown vertically upwards to reach a height of 91.5 m?
$T a k e a = 9.8 \frac{m}{s^{2}}$

With what speed must an object be thrown vertically upwards to reach a height of 91.5 m? (Take $g = 9.8 m s^{- 2}$ )

a = 9.8 m s^{- 2}

1 m / s = 2.23 m i / h

91.5 m

(T a k e g = 10 m / s^{2})

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