With what speed must an object be thrown vertically upwards to reach a height of 125 m? $(T a k e g = 10 m / s^{2})$

20 m/s

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30 m/s

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40 m/s

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50 m/s

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Solution

The correct option is D 50 m/s

When an object is thrown upward, its velocity starts to reduce and becomes zero at the highest position.

Here, the acceleration due to gravity is uniform and opposite to the direction of velocity.

Therefore,
$s = 125 m, v = 0 m / s, a = - 10 m s^{- 2}, u = ?$
Using the third equation of motion,
$v^{2} - u^{2} = 2 a s$
$0^{2} - u^{2} = 2 \times (- 10) \times 125$
$u = 50 m / s$

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Similar questions

a = 9.8 m s^{- 2}

With what speed in miles/hr must an object be thrown vertically upwards to reach a height of 91.5m.

With what speed must an object be thrown vertically upwards to reach a height of 91.5 m? (Take $g = 9.8 m s^{- 2}$ )

With what speed in $\frac{m i l e s}{h r}$ must an object be thrown vertically upwards to reach a height of 91.5 m?
$T a k e a = 9.8 \frac{m}{s^{2}}$

10 m

g = 9.8 m s^{- 2}

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