With $Z n - C u$ couple and $C_{2} H_{5} O H$ , ethyl iodide reacts to give:

ether

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diethyl ether

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iodoform

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ethane

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Solution

The correct option is D ethane
The reaction takes place as:

$C_{2} H_{5} - I + 2 [H] Z n - C u, C_{2} H_{5} - O H - ----------- \to C_{2} H_{6} + H I$

Option D is correct.

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