Question

Work done in moving a 50 kg block through a horizontal distance of 10 m by applying a force of 100 N which makes an angle of ${60}^{\circ }$ with the horizontal is :

• A. 200 joule
• B. 425 joule
• C. 500 joule
• D. 575 joule

Answer 1

Answer: (C)

500 joule

We know
W$=$FScos$\theta$
$=100\times 10\times cos{60}^0$
So, W$=$500Joule(N-M)