wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Work Done in reversible adiabatic process is given by:

A
2.303 RT logV2V1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
nR(γ1)(T2T1)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2.303 RT logV1V2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B nR(γ1)(T2T1)
We know, from first law, ΔU=q+w.
For adibatic process, q=0.
Also ΔU = nCvdT and w = ΔU = nR(γ1)(T2T1).
These are the derived formula for Wrev in adiabatic process.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon