Work done on the gas, $w$ , in an irreversible expansion is given by $w = - P_{e x t} \times d V$ , where $P_{e x t}$ is the external pressure and $d V$ is the change in volume of the gas (i.e., $V_{f l o a t} - V_{i n i t i a l}$ ). What is the value of work done on $1$ mole of an ideal gas when it expands into a vacuum?

0

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8.314

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2.27

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Infinite

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Solution

The correct option is A $0$ J
Solution:- (A) $0 J$
$W = - P_{e x t .} \times d V$
Given that the gas is expanding in the vacuum.
As we know that the external pressure in the vacuum is $0$ .
$∴ W = - 0 \times d V = 0$
Hence the work done will be $0 J$ .

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Work done on the gas, w, in an irreversible expansion is given by w=−Pext×dV, where Pext is the external pressure and dV is the change in volume of the gas (i.e., Vfloat−Vinitial). What is the value of work done on 1 mole of an ideal gas when it expands into a vacuum?

The correct option is A 0 JSolution:- (A) 0JW=−Pext.×dVGiven that the gas is expanding in the vacuum.As we know that the external pressure in the vacuum is 0.∴W=−0×dV=0Hence the work done will be 0J.

The correct option is A $0$ J
Solution:- (A) $0 J$
$W = - P_{e x t .} \times d V$
Given that the gas is expanding in the vacuum.
As we know that the external pressure in the vacuum is $0$ .
$∴ W = - 0 \times d V = 0$
Hence the work done will be $0 J$ .