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Energy Levels

Work function...

Question

Work function of metal A is equal to the ionization energy of hydrogen atom in the first excited state. Work function of metal B is equal to the ionization energy of $H e^{+}$ ion in the second orbit. Photons of same energy E are incident on both A and B. Maximum kinetic energy of photoelectrons emitted from A is twice that of photoelectron emitted from B.
The difference in maximum kinetic energy of photoelectrons from A and from B.

A

increases with increase in E

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B

decreases with increase in E

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C

first increases then decreases with increase in E

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D

remains constant

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Solution

The correct option is D remains constant
$(E - ϕ_{A}) - (E - ϕ_{B}) = ϕ_{B} - ϕ_{A}$
=10.2 eV = constant

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