Work out the following-12-15-7-15

The denominator of both fractions is the same so we can subtract them directly.12/15 7/15=12 7/15=5/15 Reduce the 5/15 into simplest form5/15=1/3Hence, 1/3 is ...

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Standard VI

Mathematics

Fractions

Work out the ...

Question

Work out the following:
$\frac{12}{15}$ $-$ $\frac{7}{15}$

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Solution

The denominator of both fractions is the same so we can subtract them directly.
$\frac{12}{15}$ $-$ $\frac{7}{15}$ $=$ $\frac{12 - 7}{15} = \frac{5}{15}$
Reduce the $\frac{5}{15}$ into simplest form
$\frac{5}{15}$ $= \frac{1}{3}$
Hence, $\frac{1}{3}$ is the required solution.

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Similar questions

Work out the following:

$\frac{8}{15} + \frac{3}{15}$

Q. Carry out the following multipliclations:

(1) 12 × (−3)
(2) (−6) × 4
(3) (−15) × (−5)
(4) 35 × 8
(5) (−38) × (−2)
(6) 15 × (−61)

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Name the property of multiplication illustrated by each of the following statements :

(i) $\frac{- 15}{8} \times \frac{- 12}{7} = \frac{- 12}{7} \times \frac{- 15}{8}$

(ii) $(\frac{- 2}{3} \times \frac{7}{9}) \times \frac{- 9}{5} = \frac{- 2}{3} \times (\frac{7}{9} \times \frac{- 9}{5})$

(iii) $\frac{- 3}{4} \times (\frac{- 3}{4} \times \frac{- 5}{6}) + (\frac{- 3}{4} \times \frac{7}{8})$

(iv) $\frac{- 16}{9} \times 1 = 1 \times \frac{- 16}{9} = \frac{- 16}{9}$

(v) $\frac{- 11}{15} \times \frac{15}{- 11} = \frac{15}{- 11} \times \frac{- 11}{15} = 1$

(vi) $\frac{- 7}{5} \times 0 = 0$

Q. The distance (in km) of

40

engineers from their residence to their place of work were found as follows:

\begin{matrix} 5 & 3 & 10 & 20 & 25 & 11 & 13 & 7 & 12 & 31 19 & 10 & 12 & 17 & 18 & 11 & 32 & 17 & 16 & 2 7 & 9 & 7 & 8 & 3 & 5 & 12 & 15 & 18 & 3 12 & 14 & 2 & 9 & 6 & 15 & 15 & 7 & 6 & 12 \end{matrix}

What is the empirical probability that an engineer lives:
(i) less than

7 k m

from her place of work?
(ii) more than or equal to

7 k m

from her place of work?
(iii) within

\frac{1}{2} k m

from her place of work?

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Work out the following:1215-715

The denominator of both fractions is the same so we can subtract them directly.1215-715=12-715=515 Reduce the 515 into simplest form515=13Hence, 13 is the required solution.

Work out the following:
$\frac{12}{15}$ $-$ $\frac{7}{15}$

The denominator of both fractions is the same so we can subtract them directly.
$\frac{12}{15}$ $-$ $\frac{7}{15}$ $=$ $\frac{12 - 7}{15} = \frac{5}{15}$
Reduce the $\frac{5}{15}$ into simplest form
$\frac{5}{15}$ $= \frac{1}{3}$
Hence, $\frac{1}{3}$ is the required solution.