workdone in moving a 5C charge across a conductor is 100J.if the potential at one end of a conductor is 10V.find the potential at the other end of the conductor
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Solution
Workdone by charge = q. Δv [given the charge is positive] 100 = 5 (V1 - V2) [ since, workdone is positive, it means Δv is also positive] 100/5 = V1 - V2 20 = V1 - V2 V1 = 20 + V2 = 20 + 10 = 30 V