Question

Write a balanced chemical equation for the following:

Action of dilute Sulphuric acid on Zinc sulphide.

Answer 1

When Zinc Sulphide$\mathbf{\left(}\mathbf{ZnS}\mathbf{\right)}$ and Sulphuric acid$\mathbf{\left(}{\mathbf{H}}_{\mathbf{2}}{\mathbf{SO}}_{\mathbf{4}}\mathbf{\right)}$ react with each other then it results in the formation of Zinc Sulphate$\mathbf{\left(}{\mathbf{ZnSO}}_{\mathbf{4}}\mathbf{\right)}$ and liberate Hydrogen Sulphide gas$\mathbf{\left(}{\mathbf{H}}_{\mathbf{2}}\mathbf{S}\mathbf{\right)}$.

Balanced chemical equation:-

$\underset{\mathrm{Zinc}\mathrm{sulphide}}{\underbrace{\mathrm{ZnS}\left(\mathrm{s}\right)}}+\underset{\mathrm{Sulphuric}\mathrm{acid}}{\underbrace{{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)}}\to \underset{\mathrm{Zinc}\mathrm{sulphate}}{\underbrace{{\mathrm{ZnSO}}_4\left(\mathrm{aq}\right)}}+\underset{\mathrm{Hydrogen}\mathrm{sulphide}}{\underbrace{{\mathrm{H}}_2\mathrm{S}\left(\mathrm{g}\right)}}$