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Acids and Bases in Water

Write a balan...

Question

Write a balanced equation for the following:
Red lead is warmed with concentrated hydrochloric acid.

{P b}_{3} O_{4} + 16 H C l \to 3 P b C l + {8 H}_{2} O + {5 C l}_{2}

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{2 P b}_{3} O_{4} + 8 H C l \to 6 P b C l + {8 H}_{2} O + {C l}_{2}

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{2 P b}_{3} O_{4} + 16 H C l \to 6 P b C l + {8 H}_{2} O + {5 C l}_{2}

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{44 P b}_{3} O_{4} + 16 H C l \to 12 P b C l + {8 H}_{2} O + {C l}_{2}

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Solution

The correct option is C ${2 P b}_{3} O_{4} + 16 H C l \to 6 P b C l + {8 H}_{2} O + {5 C l}_{2}$

Suggest Corrections

Similar questions

2 K M n O_{4} + 16 H C l \to 5 C l_{2} + 2 M n C l_{2} + 2 K C l + 8 H_{2} O

K M n O_{4} + H_{2} S O_{4} + H C l \to K_{2} S O_{4} + M n S O_{4} + C l_{2} + H_{2} O

{2 m n O}_{4}^{-} + 6 H^{+} + {5 H}_{2} C_{2} O_{4} ⇌ {2 M N}^{2 +} + 8 H_{2} O + {10 C O}_{2}

E_{{M n O}_{4} M n^{2 +},}^{0} = 1.51 V

E_{{C O}_{3} C_{2} O_{4}^{2 -}}^{0} = - 0.49 V

C l_{2}

2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 8 H_{2} O + 5 C l_{2}

1 L

K M n O_{4}

79 %

K M n O_{4}

9 L H C l

d = 1.825

10 %

H C l

80 %

2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 5 C l_{2} + 8 H_{2} O

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