Question

Write a Pythagorean triplet whose one member is $16$.

Answer 1

REF. Image.

We know the basic Pythagorean

triplet 3, 4 and 5.

Let us construct a triangle which have sides in a multiple of 3, 4 & 5.

here $AB=3a$

$BC=4a$

& let, get AC as 5a

From Pythagoras theorem

where $aϵz^{+}$

$A{C}^2=A{B}^2+B{C}^2$

$=(3a{)}^2+(4a{)}^2$

$=9a^2+16a^2$

$A{C}^2=25a^2$

$AC=5a$

So, Let us put a = 4 we get

AB = 12, BC = 16 & AC = 20.

So, We have Pythagorean triplet:

12, 16 and 20.