Question

Write a Pythagorean triplet whose one number is:
(i) 6
(ii) 14
(iii) 16
(iv) 18

Answer 1

$2m,m^2+1,m^2-1$ form a Pythagorean triplet for any number.
(i) $2m=6$
$\Rightarrow m=3$
So, Pythagorean triplets are $6,10,8$
(ii) $2m=14$
$\Rightarrow m=7$
So, Pythagorean triplets are $7,48,50$

(iii) $2m=16$
$\Rightarrow m=8$
So, Pythagorean triplets are $16,63,65$

(iv) $2m=18$
$\Rightarrow m=9$
So, Pythagorean triplets are $18,80,82$