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Question

Write an equation of the line parallel to the line x=5 and passing through the point (3,10)

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Solution

Given line parallel to x=5 and passes through point (3,10)
So to find equation of line
Slope of line joining x=5 and the parallel to it will be same m=
So the equation of line having m=10= and passing through (3,10) will be
y=mx+C10=10×3+CC=3
On substituting the value in C we get
y=10x+(3)x=3
Hence this is the equation of required line.

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