Find an equation of the line parallel to the line $3 x + 6 y = 5$ and passing through the point $(1, 3)$ . Write an equation in the slope intercept form.

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Solution

Solution:
$L_{1} : 3 x + 6 y = 5$
Slope of the line $L_{1} = \frac{- 1}{2}$
Since required line is parallel to $L_{1}$ so slope the required line $= \frac{- 1}{2}$
The equation of the line having slope $= \frac{- 1}{2}$ and passing through $(1, 3)$ is
$(y - 3) = \frac{- 1}{2} (x - 1)$
or, $2 y - 6 = - x + 1$
or, $x + 2 y = 5$

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