Question

Write balanced equations for the following reaction:
reduction of Copper oxide by hydrogen

Answer 1

• When a metal oxide is reduced by a reducing agent, the product obtained is a metal atom.
• The reaction of Copper oxide ($CuO$) with Hydrogen ($H_2$) yields Copper ($Cu$) atom and water
• .$$\begin{gathered} CuO+H_2\stackrel{∆}{\to }Cu+H_{2}O \\ CopperCopper \\ oxide \end{gathered}$$
• Here Copper is reduced from $+2$ to $0$ oxidation state.
• Here both sides the number of atoms are balanced.