Question

Write $\frac{120m^2{n}^{-3}}{60m^5{n}^{-2}}$ in simplest form using only positive exponents. Assume that $m\ne 0$ and $n\ne 0$.

• A. $\frac{2n}{m^3}$
• B. $\frac{2}{m^{3}n}$
• C. $\frac{{2m}^3}{n}$
• D. $\frac{1}{{2m}^{3}n}$

Answer 1

Answer: (B)

$\frac{2}{m^{3}n}$

Given $\frac{120m^2{n}^{-3}}{60m^5{n}^{-2}},m\ne 0,n\ne 0$

$=\frac{120m^2{n}^{-3}}{60m^5{n}^{-2}}$

$=\frac{2\times n^{(-3+2)}}{m^{(5-2)}}$

$=\frac{2n^{-1}}{m^3}$

$=\frac{2}{m^3{n}^{}}$