Write down the structure of the following molecule and comment on aromaticity?

B_{3} H_{3} O_{3}

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C_{3} N_{3} (N H_{2})_{3}

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Trimer of isocyanic acid

(H N = C = O)_{3}

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None of the above

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Solution

The correct option is B $B_{3} H_{3} O_{3}$
Aromatic as it is planar contain $6 π$ electron, $s p^{2}$ hybridized atoms.

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Similar questions

H - N = C = O I \leftrightarrow H - ⊖ N - C \equiv \oplus O I I \leftrightarrow H - \oplus N \equiv C - ⊖ O I I I

B a C^{*} O_{3} + H_{2} S O_{4} \to X_{(g a s)}, (C^{*} d e n o t e s^{14})

H C l

(HN O_{3})

(H_{2} S O_{4})

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