Write equations for the reaction of dil. HCl with each of the following.
Sodium sulphite

2 H C l + {N a}_{2} S O_{3} \to 2 N a C l + S O_{2} + H_{2} O

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4 H C l + {N a}_{2} S O_{3} \to 2 N a C l + S O_{2} + 2 H_{2} O

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2 H C l + {N a}_{2} S O_{3} \to N a C l + S O_{2} + H_{2} O

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2 H C l + {N a}_{2} S O_{3} \to 2 N a C l + S O_{3} + H_{2} O

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Solution

The correct option is A $2 H C l + {N a}_{2} S O_{3} \to 2 N a C l + S O_{2} + H_{2} O$
$2 H C l + {N a}_{2} S O_{3} \to 2 N a C l + S O_{2} + H_{2} O$

Here, atoms of respective elements are balanced on product and reactant sides, following law of conservation of mass.

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Similar questions

{N a}_{2} S_{2} O_{3}

{N a}_{2} S_{2} O_{3} + H_{2} O + {C l}^{2} \to {N a}_{2} {S O}_{4} + 2 H C l + S

{N a}_{2} S_{2} O_{3}

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N a_{2} S_{2} O_{3}

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