Write IUPAC names:
$C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C O O H$

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Solution

The given compound is :
$C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C O O H$
Its IUPAC name is hexanoic acid.

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I U P A C

C H_{3} - C H_{2} - C H_{2} - C O O H

C H_{3} - C H_{2} - C H | C O O H - C H_{2} - C l | C H - C H_{2} - C H_{3}

C H_{3} - C H_{2} - C H_{2} - C H (C H_{3}) - C H_{3}

C H_{3} - C H (C H_{2} - C H_{3}) - C H_{2} - C H_{2} - C H_{3}

C H_{3} - C H_{2} - C H_{2} - C H = C H_{2}

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