Write $I U P A C$ names of the following compound:

$C H_{2} = C H - C \equiv C - C H_{3}$

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Solution

The correct IUPAC name of the compound $1 C H_{2} = 2 C H - 3 C \equiv 4 C - 5 C H_{3}$ is pent-1-ene-3-yne. Using lowest locant rule the numbering starts from the alkene group.
The parent hydrocarbon contains 5 carbon atoms and a double bond and a triple bond.

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