Write Lewis symbols for the following atoms and ions:

S and S^2–; Al and Al³⁺; H and H^–

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Solution

(i) S and S^2–

The number of valence electrons in sulphur is 6.

The Lewis dot symbol of sulphur (S) is .

The dinegative charge infers that there will be two electrons more in addition to the six valence electrons. Hence, the Lewis dot symbol of S^2– is .

(ii) Al and Al³⁺

The number of valence electrons in aluminium is 3.

The Lewis dot symbol of aluminium (Al) is.

The tripositive charge on a species infers that it has donated its three electrons. Hence, the Lewis dot symbol is .

(iii) H and H^–

The number of valence electrons in hydrogen is 1.

The Lewis dot symbol of hydrogen (H) is .

The uninegative charge infers that there will be one electron more in addition to the one valence electron. Hence, the Lewis dot symbol is .

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(iii)

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In the Lewis dot structure of Al3+ , we should draw 8 dots or to write Al only without any dot ?

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