Question

Write the additive inverse of each of the following.
$\left(i\right)\frac{2}{8}$
$\left(ii\right)\frac{2}{-9}$
$\left(iii\right)\frac{-19}{-6}$

Answer 1

If $‘a^{\prime }$ is any number then the additive inverse of $‘a^{\prime }$ will be $‘-a^{\prime }$.

Therefore,
$\left(i\right)\frac{2}{8}$
The additive inverse of $\frac{2}{8}=\frac{-2}{8}$

$\left(ii\right)\frac{2}{-9}=\frac{-2}{9}$
The additive inverse of $\frac{-2}{9}=\frac{2}{9}$

$\left(iii\right)\frac{-19}{-6}=\frac{19}{6}$
The additive inverse of $\frac{19}{6}=\frac{-19}{6}$