Write the balanced chemical reaction for the conversion of sulphur to sulphuric acid.

S + H N O_{3} (h o t a n d c o n c .) \to H_{2} {S O}_{4} + {2 H}_{2} O + {N O}_{2}

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S + 6 {H N O}_{3} (h o t a n d c o n c .) \to H_{2} {S O}_{4} + {2 H}_{2} O + {6 N O}_{2}

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2 S + 6 {H N O}_{3} (h o t a n d c o n c .) \to 2 H_{2} {S O}_{4} + {2 H}_{2} O + {6 N O}_{2}

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2 S + 3 {H N O}_{3} (h o t a n d c o n c .) \to 2 H_{2} {S O}_{4} + {2 H}_{2} O + {3 N O}_{2}

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Solution

The correct option is A $S + 6 {H N O}_{3} (h o t a n d c o n c .) \to H_{2} {S O}_{4} + {2 H}_{2} O + {6 N O}_{2}$
Sulphur reacts with nitric acid to form sulphuric acid.

$S + 6 {H N O}_{3} (h o t a n d c o n c) \to H_{2} {S O}_{4} + {2 H}_{2} O + {6 N O}_{2}$

Hence, option B is correct.

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