Write the balanced chemical reaction for the following conversion: Chlorine to sulphuric acid.

2 {S O}_{2} + 2 H_{2} O + 2 {C l}_{2} \to 4 H C l + H_{2} {S O}_{4}

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{S O}_{2} + H_{2} O + {C l}_{2} \to H C l + H_{2} {S O}_{4}

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2 {S O}_{2} + 2 H_{2} O + {C l}_{2} \to 2 H C l + 2 H_{2} {S O}_{4}

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{S O}_{2} + 2 H_{2} O + {C l}_{2} \to 2 H C l + H_{2} {S O}_{4}

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Solution

The correct option is D ${S O}_{2} + 2 H_{2} O + {C l}_{2} \to 2 H C l + H_{2} {S O}_{4}$
${S O}_{2} + 2 H_{2} O + {C l}_{2} \to 2 H C l + H_{2} {S O}_{4}$
Chlorine reacts with sulphur dioxide to form sulphuric acid and hydrochloric acid.

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P b S + 4 O_{3} \to P b S O_{4} + . . . . . . . . . . . . . . .

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