Write the balanced equation for the following reaction :

Potassium hydrogen carbonate and dilute sulphuric acid.

{2 K H C O}_{3} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {2 H}_{2} O + {2 C O}_{2}

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{4 K H C O}_{3} + H_{2} {S O}_{4} \to 2 K_{2} {S O}_{4} + {2 H}_{2} O + {2 C O}_{2}

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{2 K H C O}_{3} + 3 H_{2} {S O}_{4} \to 3 K_{2} {S O}_{4} + {2 H}_{2} O + {2 C O}_{2}

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{2 K H C O}_{3} + 2 H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {4 H}_{2} O + {2 C O}_{2}

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Solution

The correct option is A ${2 K H C O}_{3} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {2 H}_{2} O + {2 C O}_{2}$
${2 K H C O}_{3} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {2 H}_{2} O + {2 C O}_{2}$

Potassium hydrogen carbonate reacts with dilute sulphuric acid to form potassium sulphate, carbon dioxide and water.

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H_{2} {S O}_{4}

(a) H_{2} {S O}_{4} + N a O H \to N a H {S O}_{4} + H_{2} O

(b) H_{2} {S O}_{4} + 2 N a O H \to {N a}_{2} {S O}_{4} + 2 H_{2} O

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K M {n O}_{4} + H_{2} C_{2} O_{4} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {M n S O}_{4} + {C O}_{2} + H_{2} O

{N a}_{2} {S O}_{4}

N a O H

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{2 S O}_{2} + O_{2} 450^{0} C - -- \to V_{2} O_{2} {2 S O}_{x} {S O}_{3} + H_{2} {S O}_{4} \to H_{2} S_{2} O_{y} H_{2} S_{2} O_{7} + H_{2} O \to 2 H_{2} {S O}_{4}

K_{2} {C r}_{2} O_{7} + {a H}_{2} {S O}_{4} + {b S O}_{2} \to K_{2} {S O}_{4} + {C r}_{2} {(S O}_{4})_{3} + {c H}_{2} O

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