Write the balanced equation for the reaction between a mixture of ammonium chloride and slaked lime.

{2 N H}_{4} C l + 2 C a {(O H)}_{2} \to 2 {N H}_{3} + 2 {C a C l}_{2} + {2 H}_{2} O

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{2 N H}_{4} C l + C a {(O H)}_{2} \to 2 {N H}_{3} + {C a C l}_{2} + {2 H}_{2} O

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{N H}_{4} C l + C a {(O H)}_{2} \to {N H}_{3} + {C a C l}_{2} + {2 H}_{2} O

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{N H}_{4} C l + 2 C a {(O H)}_{2} \to {N H}_{3} + 2 {C a C l}_{2} + {2 H}_{2} O

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Solution

The correct option is B ${2 N H}_{4} C l + C a {(O H)}_{2} \to 2 {N H}_{3} + {C a C l}_{2} + {2 H}_{2} O$

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Q. How many grams of ammonia is obtained when 32.6 g of ammonium chloride reacts with calcium hydroxide during the laboratory preparation of ammonia?

[2 N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + 2 H_{2} O + 2 N H_{3}]

[N=14, H=1, O=16, S=32, Cl=35.5]

(a) Calculate the mass fo ammonia that can be obtained from 21.4 g of $N H_{4} C l$ by the reaction:
$2 N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + 2 H_{2} O + 2 N H_{3}$
(b) what will be ht volume of ammonia when measured at STP?

Q. Balance the reaction.

N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + N H_{3} + H_{2} O

Balance the following equation b hit and trial method :. NH4Cl + Ca(OH)2 ------------> CaCl2 + H2O + NH3

The secondary reactions which takes place in dry cell are:

1) $M n O_{2} + N H_{4}^{+} + e^{-} \to M n O (O H) + N H_{3}$

2) $2 N H_{4} C l + 2 (O H^{-}) \to$ $2 N H_{3} + 2 C l^{-} + 2 H_{2} O$

3) $Z n + 2 M n O_{2} \to$ $[Z n (N H_{3})_{2}] + 2 O H^{-} + 2 M n O (O H)$

4) $Z n^{2 +} 2 N H_{3} + 2 C l^{-} \to$ $[Z n (N H_{3})_{2}] C l_{2} or Z n C l_{2} .2 N H_{3}$

Correct statements are:

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Write the balanced equation for the reaction between a mixture of ammonium chloride and slaked lime.

The correct option is B 2NH4Cl+Ca(OH)2→2NH3+CaCl2+2H2O

The correct option is B ${2 N H}_{4} C l + C a {(O H)}_{2} \to 2 {N H}_{3} + {C a C l}_{2} + {2 H}_{2} O$