Write the balanced equation of reduction of copper oxide by hydrogen.

Open in App

Solution

When Copper oxide reacts with hydrogen gas, the Copper oxide is reduced to copper metal, and water is formed.
The chemical equation for the reaction can be written as:
$CuO (s) + H_{2} (g) \to Cu (s) + H_{2} O (l) (Copper (Hydrogen) (Copper) (Water) oxide)$

Suggest Corrections

Similar questions

Q. Write balanced equations for the following reactions:
(a) reduction of copper oxide by hydrogen.
(b) reduction of iron (III) oxide by carbon monoxide.
(c) reduction of lead (II) oxide by carbon.

(a) Explain the following in terms of gain or loss of oxygen with one example each :

(i) oxidation (ii) reduction

(b) When copper powder is heated strongly in air, it forms copper oxide. Write a balanced chemical equation for this reaction. Name (i) substance oxidised, and (ii) substance reduced.

Q. Write balanced chemical equations for the reduction between copper oxide by hydrogen.

Write balanced equations for the following reaction:
reduction of Copper oxide by hydrogen

Write balanced equations for the reduction of Lead $(I I)$ oxide by carbon

Join BYJU'S Learning Program

Write the balanced equation of reduction of copper oxide by hydrogen.

When Copper oxide reacts with hydrogen gas, the Copper oxide is reduced to copper metal, and water is formed.The chemical equation for the reaction can be written as:CuO(s)+H2(g)→Cu(s)+H2O(l)(Copper(Hydrogen)(Copper)(Water)oxide)

When Copper oxide reacts with hydrogen gas, the Copper oxide is reduced to copper metal, and water is formed.
The chemical equation for the reaction can be written as:
$CuO (s) + H_{2} (g) \to Cu (s) + H_{2} O (l) (Copper (Hydrogen) (Copper) (Water) oxide)$