Write the dimensions of (a×b) in the relation E=b−x2at, where E is the energy, x is the displacement and t is time.
A
[ML2T]
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B
[M−1L2T]
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C
[ML2T−1]
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D
[M−1L2T−1]
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Solution
The correct option is B[M−1L2T] Given relation is E=b−x2at,
so, here b and x2 should have same dimension i.e. [b]=[L2]
Also, [a]=[b−x2][E][t] ⇒[a]=[L2][ML2T−2][T]=[M−1T]
Thus, we have [a×b]=[M−1T][L2]=[M−1L2T]