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Question

Write the discriminant of the following quadratic equations:
(i) 2x25x+3=0 (ii) x2+2x+4=0
(iii) (x1)(2x1)=0 (iv) x22x+k=0,kϵR
(v) 3x2+22x23=0 (vi) x2x+1=0

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Solution

The discriminant of a quadratic equation a x squared plus b x plus c equals 0 is given by
D equals b squared minus 4 a c
Where,
D= discriminant of the quadratic equation,
a = coefficient of x2 in the quadratic equation,
b = coefficient of x in the quadratic equation,
c = any integer present in the equation,

Now,
(i) D = left parenthesis negative 5 right parenthesis squared minus 4 left parenthesis 2 right parenthesis left parenthesis 3 right parenthesis equals 25 minus 24 equals 1

(ii) D = left parenthesis 2 right parenthesis squared minus 4 left parenthesis 1 right parenthesis left parenthesis 4 right parenthesis equals 4 minus 16 equals negative 12

(iii)
left parenthesis x minus 1 right parenthesis left parenthesis 2 x minus 1 right parenthesis equals 0 2 x squared minus 3 x plus 1 equals 0 D space equals space left parenthesis negative 3 right parenthesis squared minus 4 left parenthesis 2 right parenthesis left parenthesis 1 right parenthesis equals 9 minus 8 equals 1

(iv)
D equals left parenthesis negative 2 right parenthesis squared minus 4 left parenthesis k right parenthesis left parenthesis 1 right parenthesis equals 4 minus 4 k equals 4 left parenthesis 1 minus k right parenthesis

(v)
D equals left parenthesis 2 square root of 2 right parenthesis squared minus 4 left parenthesis square root of 3 right parenthesis left parenthesis negative 2 square root of 3 right parenthesis equals 8 plus 24 equals 32

(vi)
D equals left parenthesis negative 1 right parenthesis squared minus 4 left parenthesis 1 right parenthesis left parenthesis 1 right parenthesis equals 1 minus 4 equals negative 3


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