Write the equation for the reaction taking place during the electrolysis of Lead bromide?

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Solution

Lead bromide in its molten state undergoes electrolysis and conducts electricity.
Electrolytic dissociation of Lead bromide produces lead ions and bromide ions.
$\underset{L e a d b r o m i d e}{P b B r_{2}} \leftrightarrow \underset{L e a d i o n s}{P b^{2 +}} + \underset{B r o m i d e i o n s}{2 B r^{-}}$
The lead ions will move towards the cathode and undergo reduction while the bromide ions move towards the anode and undergo oxidation by losing their electron.
So the anodic and cathodic reaction is,
Anode: $P b^{2 +} + 2 e^{-} \to \underset{L e a d}{P b}$
Cathode: $B r^{-} \to B r + e^{-}$

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