Question

Write the equation taking place at the anode during the purification of the Anode?

Answer 1

• Copper is purified by the process of electrolysis.
• The electrolyte used is Copper sulfate($\mathit{C}\mathit{u}\mathit{S}{\mathit{O}}_{\mathbf{4}}$), the anode is impure and the cathode is pure copper.
• The cathodic and anodic reaction is,

Cathode: $\underset{Copperion}{C{u}^{2+}}+2e^{-}\to \underset{Copper}{Cu\left(s\right)}$

Anode: $\underset{Copper}{Cu\left(s\right)}\to \underset{Copperion}{C{u}^{2+}}+2e^{-}$

So the Anode reaction is,

Anode: $\underset{Copper}{Cu\left(s\right)}\to \underset{Copperion}{C{u}^{2+}}+2e^{-}$