Question

Write the equation when Ethene reacts with water.

Answer 1

The molecular formula of Ethene is ${\mathrm{C}}_2{\mathrm{H}}_4$.

Ethene $\left({\mathrm{C}}_2{\mathrm{H}}_4\right)$ and water($H_{2}O$):

1. When Ethene gas $\left({\mathrm{C}}_2{\mathrm{H}}_4\right)$ reacts with water it undergoes hydration to form Ethyl alcohol $\left({\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}\right)$ bypassing its vapors through water in the presence of Sulphuric acid$\left({\mathrm{H}}_2{\mathrm{SO}}_4\right)$.
2. This reaction is called hydration of Ethane ($C_2{H}_6$).
   The chemical reaction is as follows $\underset{\mathrm{Ethene}}{{\mathrm{C}}_2{\mathrm{H}}_4}+\underset{\mathrm{Water}}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}\stackrel{{\mathrm{H}}_2{\mathrm{SO}}_4}{\to }\underset{\mathrm{Ethyl}\mathrm{alcohol}}{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}\left(\mathrm{l}\right)}$