Write the first five terms of the following arthmetic progression where first term a=3, common difference d=4.
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Solution
Here, a=3 and d=4 tn=a+(n−1)d Hence, t1=a=3 t2=a+d=3+4=7 t3=a+2d=3+8=11 t4=a+3d=3+12=15 t5=a+4d=3+16=19 ∴ The first five terms of the A.P. are 3,7,11,15,19.