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Question

Write the first five terms of the following arthmetic progression where first term a=3, common difference d=4.

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Solution

Here, a=3 and d=4
tn=a+(n1)d
Hence, t1=a=3
t2=a+d=3+4=7
t3=a+2d=3+8=11
t4=a+3d=3+12=15
t5=a+4d=3+16=19
The first five terms of the A.P. are 3,7,11,15,19.

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