MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Valency and Oxidation States

Write the for...

Question

Write the formula for the following compound.
Iron (III) sulphate

Open in App

Solution

As Iron has $+ 3$ oxidation state $(I I I)$ , and sulphate has always $- 2$ charge.

So to neutralize both cation and anion, the total charge must be equal:
$2 \times (+ 3) = 3 \times (- 2)$
Hence there must be $2$ atoms of $F e$ and $3 S O_{4}$ units in formula.
Hence, the formula must be $F e_{2} (S O_{4})_{3}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Formula for the following compound Iron (III)sulphate is

F e_{2} (S O_{4})_{3}

.

Q. Write the formula of the following compounds:
(i) Potassium trioxalatoaluminate (III)
(ii) Hexaaquairon(II) sulphate.

Q. (a) Write the balanced equations for the preparation of the following compounds (as the major product), starting from iron and using only one other substance:
(i) iron (II) chloride
(ii) iron (III) chloride
(iii) iron (II) sulphate
(iv) iron (II) sulphide
(b) Write the equations for the laboratory preparation of
(i) sodium sulphate using dilute sulphuric acid.
(ii) lead sulphate using dilute sulphuric acid.

Q. Using IUPAC norms write the formulae for the following : (i) Hexaamminecobalt(III) sulphate (ii) Potassium trioxalatochromate(III)

The formula of iron (III) sulphate is _______ .

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Higher Elements, Oxidation State

CHEMISTRY

Watch in App

explore_more_icon

Explore more

NCERT - Standard XII

Valency and Oxidation States

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon