Question

Write the IUPAC name of the following compounds:

i) ${\left({CH}_3\right)}_{2}CHCH\left(Cl\right){CH}_3$

ii) ${CH}_3{CH}_{2}C{\left({CH}_3\right)}_2{CH}_{2}I$
iii) ${CH}_{3}CH\left({CH}_3\right)CH\left(Br\right){CH}_3$
iv) ${CH}_{3}C\left(Cl\right)\left(C_2{H}_5\right){CH}_2{CH}_3$
v) ${CH}_{3}CH=CHC\left(Br\right){\left({CH}_3\right)}_2$

Answer 1

Solution:-

• $\left(i\right)C{H}_3-\stackrel{\underset{|}{C{H}_3}}{CH}-\stackrel{\underset{|}{Cl}}{CH}-C{H}_3$
  

The IUPAC name of the above compound is $2$-chloro-$3$-methylbutane.

Here $2$-chloro is for the chloride group $(-Cl)$ attached at position $C-2$ while $3$-methyl is for the methyl group $(-C{H}_3)$ attached at the position $C-3$ and butane is for the long chain of $4$ carbon atoms.

Hence the IUPAC name of the above compound is $2$-chloro-$3$-methylbutane.

• $\left(ii\right)C{H}_3-C{H}_2-\underset{\stackrel{|}{C{H}_3}}{\stackrel{\underset{|}{C{H}_3}}{C}}-\stackrel{\underset{|}{I}}{C{H}_2}$
  

The IUPAC name of the above compound is $1$-iodo-$2,2$-dimethyl butane.

Here $1$-iodo is for the iodide group $(-I)$ attached at position $C-1$ while $2,2$-dimethyl is for the $2$ methyl groups $(-C{H}_3)$ attached at the same position $C-3$ and butane is for the long chain of $4$ carbon atoms.

Hence the IUPAC name of the above compound is $1$-iodo-$2,2$-dimethyl butane.

• $\left(iii\right)C{H}_3-\stackrel{\underset{|}{C{H}_3}}{CH}-\stackrel{\underset{|}{Br}}{CH}-C{H}_3$
  

The IUPAC name of the above compound is $2$-bromo-$3$-methylbutane.

Here $2$-bromo is for the bromide group $(-Br)$ attached at position $C-2$ while $3$-methyl is for the methyl group $(-C{H}_3)$ attached at the position $C-3$ and butane is for the long chain of $4$ carbons.

Hence the IUPAC name of the above compound is $2$-bromo-$3$-methylbutane.

• $\left(iv\right)C{H}_3-\underset{\stackrel{|}{C_2{H}_5}}{\stackrel{\underset{|}{Cl}}{C}}-C{H}_2-C{H}_3$
  

The IUPAC name of the above compound is $3$-chloro-$3$-methylpentane.

Here $3$-chloro is for the chloride group $(-Cl)$ attached at position $C-3$ while $3$-methyl is for the methyl group $(-C{H}_3)$ attached at the position $C-3$ and pentane is for the long chain of $5$ carbon atoms.

Hence the IUPAC name of the above compound is $3$-chloro-$3$-methyl pentane.

• $\left(v\right)C{H}_3-CH=CH-\underset{\stackrel{|}{C{H}_3}}{\stackrel{\underset{|}{Br}}{C}}-C{H}_3$
  

The IUPAC name of the above compound is $4$-bromo-$4$-methylpent-$2$-ene.

Here $4$-bromo is for the bromide group $(-Br)$ attached at position $C-4$ while $4$-methyl is for the methyl group $(-C{H}_3)$ attached at the position $C-4$ and pent-$2$-ene is for the long chain of $5$ carbon atoms havinf double bond at position $C-2$.

Hence the IUPAC name of the above compound is $4$-bromo-$4$-methylpent-$2$-ene.