Write the length of the intercept made by the circle x2-y2-2 x-4 y-5-0 on y-axis-

Since the intercept lies on the y axis, by putting x = 0 in the given equation, we get: y2 4y 5=0 #8658;y= 1, #160;5 Thus, the length of the intercept on ...

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Standard X

Mathematics

Slope Intercept Form of a Straight Line

Write the len...

Question

Write the length of the intercept made by the circle x² + y² + 2x − 4y − 5 = 0 on y-axis.

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Solution

Since the intercept lies on the y-axis, by putting x = 0 in the given equation, we get:

$y^{2} - 4 y - 5 = 0$
$\Rightarrow y = - 1, 5$

Thus, the length of the intercept on the y-axis is (5 + 1) = 6 units.

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Write the length of the intercept made by the circle x2 + y2 + 2x − 4y − 5 = 0 on y-axis.

Since the intercept lies on the y-axis, by putting x = 0 in the given equation, we get: y2-4y-5=0 ⇒y=-1, 5 Thus, the length of the intercept on the y-axis is (5 + 1) = 6 units.

Write the length of the intercept made by the circle x² + y² + 2x − 4y − 5 = 0 on y-axis.

Since the intercept lies on the y-axis, by putting x = 0 in the given equation, we get:

$y^{2} - 4 y - 5 = 0$
$\Rightarrow y = - 1, 5$

Thus, the length of the intercept on the y-axis is (5 + 1) = 6 units.