Question

Write the length of the intercept made oy the circle $x^2+Y^2+2x-4y-5=0$
on y-axis.

Answer 1

$x^2+9+2x-4y-5=0Putx=0y^2-4y-5=0y^2-5y+(y-5)=0y(y-5)+(y-5)=0(y-5)(y+1)=0y=5,-1$
Thus, circle cuts y - axis at (0, 5) and (0, -1)
so Length of intercept on y-axis by circle = 5 + 1 = 6 units.