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Question

Write the middle term in the expansion of (2x23+32x2)10.

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Solution

(2x23+32x2)10.

Here n =10, which is even number

So, (102+1)th term i.e. 6th term is the middle term.

T6=T5+1=10C5(2x23)105(32x2)5=10C5(2x23)5(32x2)5=252


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