Write the middle term in the expansion of (2x23+32x2)10.
(2x23+32x2)10.
Here n =10, which is even number
So, (102+1)th term i.e. 6th term is the middle term.
T6=T5+1=10C5(2x23)10−5(32x2)5=10C5(2x23)5(32x2)5=252
The middle term in the expansion of (2x3−32x2)2n is