Question

Write the number of protons, electrons, and neutrons present in ${}_{10}{}^{20}Ne$ element. Give the electronic configuration and draw the atomic diagram.

Answer 1

Atom is represented with its symbol having an atomic number in subscript and mass number in superscript. Symbolic representation is mentioned below :

For given element ${}_{10}{}^{20}Ne$ :

Part-1 Find number of protons, electrons and neutrons:

The atomic number $\left(\mathrm{Z}\right)$ of an element is equal to the total number of protons present in the nucleus of the atom.

Atomic number = Number of protons = Number of electrons (for electrically neutral atom)

The atomic number of neon is $10$, so it has $10$ protons and hence number of electrons are also $10$.

The mass number of elements is equal to the sum of the total number of protons and neutrons present in the nucleus of the atom.

Mass number = Number of protons + Number of neutrons

Also, Number of neutrons = Mass number - Number of protons

The number of neutrons in neon $=$$20-10=10$.

Therefore, neon have $10$ protons, $10$ electrons and $10$ neutrons.

Part-2 Electronic configuration

Electronic configuration describes the distribution of electrons in different shells like $\mathrm{K},\mathrm{L},\mathrm{M},\mathrm{N}....$with principal quantum number $\left(\mathrm{n}\right)$ value $1,2,3,4...$respectively. Accordiong to formula $2{\mathrm{n}}^2$, maximum 2 electrons can be filled in K shell, $8$ in L and so on according to the formula. Therefore, an electronic configuration is $2,8$. Neon have completely filled shells and does not gain or lose electrons, so it is inert in nature.

Shell	$\mathrm{K}$	$\mathrm{L}$
Number of electrons filled	$2$	$8$

Part-3 Atomic Diagram: