Write the number of terms in the expansion of (1−3x+3x2−x3)8.
We have, (1−3x+3x+3x2−x3)8=[(1−x)3]8=(1−x)24
So, there are 25 terms in the expansion of (1−3x2+3x2−x3)8
Middle term in the expansion of (1+3x+3x2+x3)6 is