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Preparation of Oxygen

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Question

Write the observation and result of the practical 'heating of lead nitrate and emission of nitrogen dioxide'.

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Solution

When lead nitrate is heated , it will get decompose into lead oxide , nitrogen dioxide gas and oxygen gas. Nitrogen dioxide gas is a brown gas. Lead oxide is brown coloured residue that is left. Nitrogen dioxide gas is a pungent smelling gas. The reaction will be:
${2Pb(NO}_{3})_{2} \overset{H e a t}{\to} 2 P b O + 4 N O_{2} + O_{2}$
The result of the practical is that it is a decomposition reaction.

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Q. Lead nitrate crystals on strong heating decompose to form lead monoxide, nitrogen dioxide gas and oxygen gas.

Q. When lead nitrate is heated, it breaks down into lead monoxide, nitrogen dioxide and oxygen.

2 P b (N O_{3})_{2} \to 2 P b O + 4 N O_{2} + O_{2}

The reaction is an example of:

Q. When lead nitrate is heated, it breaks down into lead monoxide, nitrogen dioxide and oxygen as given below:

2 P b (N O_{3})_{2} \to 2 P b O + 4 N O_{2} + O_{2}

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